I just wrote down the solution for the bound state of the Dirac delta potential well, for $E<0$, and apparently there is only one specific energy for the bound state, and it is negative. I solved for this just assuming $E<0$. What happens if a particle enters with energy $E<0$ but isn't equal to the bound state energy? I don't understand what the solution is telling me, that there is only one bound state, an exact figure. Does that mean we cannot say what the energy of the impinging particle is until we see what it does? I don't understand why you can't have an $E<0$ that doesn't equal the bound state energy, and if you can, what does that do? In the literature they solve for the bound state energy, then solve for the scattering coefficients for the scattering states. I guess they imply $E$ of the particle can be anything, as long as it's greater than zero. Am I wrong to think they are glossing over this too quickly? It doesn't make sense.