Background
A circuit is constructed with five resistors and a battery as shown. The battery voltage is V = 12 V. The values for the resistors are: R1 = 78 Ω, R2 = 150 Ω, R3 = 132 Ω, and R4 = 83 Ω. The value for RX is unknown, but it is known that I4, the current that flows through resistor R4, is zero.
I have a circuit constructed in the figure below (fig 1)
I've been able to solve the following, based on the battery being 12[v]
R, Ohm, I
R1, 78, 0.15384
R2, 150, 0.08
R3, 132, 0.0909
R4, 83, 0.1446
R5, 0*, 0.0
R5: $V = iR --> 12 = (0)R --> 12 != 0$
Meaning that no current or voltage pass through R5.
Problem
Here's my question:
How do I solve for the magnitude of voltage at R2?
Attempt
I was able to solve for V @ R1 by:
$$ R_{1}(i) = \frac{V}{R_{1} + R_{3}} = 0.057 [A] $$
I understand that I need to break the circuit into "systems". I know that to compute for V of R2 I need to consider V of R5, but I do not know how to calculate V or R for R5, since I'm not really sure how to handle the bridge at R4 and the fact that it's resistance has to be zero (since i=0).
My best guess so far is this:
$$ V_{2} = \frac{V R_{2}}{R_{2} X} $$
Where $X$ is a sum of R2 and R5
Summary/Closing
Any help is appreciated.