0
$\begingroup$

Reading the wikipedia of Bhabha scattering, I see that the electron-positron annihilation and electron-positron scattering are analyzed seperately. What are the differences between these two processes? Why aren't they the same process?

$\endgroup$
1
  • $\begingroup$ How can annihilation be the same as scattering? After annihilation the incoming two particles no longer exist, while after scattering, they do still exist. $\endgroup$
    – Ghoster
    Commented Oct 18, 2023 at 1:45

1 Answer 1

2
$\begingroup$

The diagram on Wikipedia (attached below) says that an $e^-$ and $e^+$ can scatter either via an exchange of a photon (second diagram) or they can totally annihilate each other, converting their energy into photons and then be recreated from the same photons. Both these processes account for a Bhabha scattering process.

On the other hand, you can have an $e^-$ and $e^+$ that simply annihilating each other. In this case, you will only be left with energy.

enter image description here

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.