0
$\begingroup$

In this paper(An Exact Cosmological Solution of the Coupled Einstein-Majorana Fermion-Scalar Field Equations), the Majorana field Lagrangian has been stated as

$\mathcal{L}_M = i \bar{\psi} \left(\gamma \wedge *\nabla\right) \psi - i m\bar{\psi}\psi*1$

where $\bar{\psi}$ is the charge conjugated spinor field $\bar{\psi}=\psi^{\dagger} \mathcal{C}$ with charge conjugation matrix, $\mathcal{C}=\gamma_0$.

In contrast to this, the same Majorana field Lagrangian has been written in this paper (Variational Field Equations of a Majorana Neutrino Coupled to Einstein’s Theory of General Relativity) as,

$\mathcal{L}_M = \dfrac{i}{2} \bar{\psi} *\gamma \wedge \nabla \psi + \dfrac{i}{2} m\bar{\psi}\psi*1$

Now even if the mass term is neglected, the rest parts of two Lagrangians aren't seem to be same in both the cases!

What am I missing and what is the correct Lagrangian for a general Majorana field in curved spacetime? Are these two Lagrangians similar (or somehow same) in some sense?

Disclaimer: I am not very much habituated in the exterior calculus, maybe that's why such confusion is arising.

$\endgroup$

1 Answer 1

4
$\begingroup$

I would write the action (in $n=2,3,4$ mod 8, spacetime dimensions where Majorana's exist) in a more conventional form as
$$ S= \int d^n x \sqrt{-g}\frac 12 \bar \psi {\mathcal C}\gamma^a e_a^\mu \left(\partial_\mu + {\textstyle \frac 12} {\omega^{bc}}_\mu \sigma_{bc}+ m\right)\psi, $$ where $\mathcal C$ is defined independently of the gamma-matrix representation by ${\mathcal C} \gamma^a {\mathcal C}^{-1} =- \gamma^{aT}$. I see no advantage to the differential form language, but it seems popular in some areas. I do think that the factor of two is correct. The $i$'s are metric-signature dependent.

I have a longer answer here: Do I need Gamma matrices in Majorana representation in the Lagrangian of a Majorana fermion?

$\endgroup$
2
  • $\begingroup$ Can you please provide me the reference, where I can find more details about this Lagrangian? $\endgroup$
    – SCh
    Oct 1, 2023 at 5:02
  • 1
    $\begingroup$ My Majorana answers are drawn from my own paper:J. Phys. A: Math. Theor. 55 ( 2022 ) 205401, arXiv:2009.00518. There are many papers on Dirac in curved space. $\endgroup$
    – mike stone
    Oct 1, 2023 at 12:27

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.