I am trying to understand the wave equation of a string fixed on both the ends, which looks like this:
$$ \frac{\partial^2 y}{\partial x^2} - \frac1{c^2}\frac{\partial^2y}{\partial t^2} - \gamma\frac{\partial y}{\partial t}- l^2\frac{\partial^4y}{\partial x^4} = 0 $$
For the below equations, $\rho$ stands for linear density, $b$ for damping coefficient, $T$ for tension, and $c$ stands for the wave's speed.
I am comfortable in the case where I do not consider damping. I could bring this result:
$$ \frac{\partial^2 y}{\partial x^2} -\frac1{c^2}\frac{\partial^2y}{\partial t^2} = 0 $$
from
$$ F = T\cdot\sin(\theta + \Delta\theta) - T\cdot\sin (\theta) $$
and $$ F = \rho\Delta x \frac{\partial ^2y}{\partial t^2} $$
However, when I take damping into consideration and derive it this way:
$$ F = T\cdot\sin(\theta + \Delta\theta) - T\cdot\sin(\theta) - b\cdot \frac {\partial y}{\partial t} $$
$$ \rho\Delta x \cdot \frac{\partial^2 y}{\partial t^2} = T\cdot \sin (\theta +\Delta \theta) - T\cdot\sin(\theta) -b\cdot\frac{\partial y}{\partial t} $$
$$ \rho\Delta x \cdot \frac{\partial^2 y}{\partial t^2} = T\cdot \tan (\theta +\Delta \theta) - T\cdot\tan(\theta) -b\cdot\frac{\partial y}{\partial t} $$
$$ \frac{\partial^2 y}{\partial t^2} = \frac1{\rho\Delta x}\left(T\cdot\left(\frac{\partial y (x+\Delta x,t)}{\partial x} - \frac{\partial y(x,t)}{\partial x}\right) - b\cdot\frac{\partial y}{\partial t}\right) $$
$$ \frac{\partial ^2y}{\partial x^2}-\frac1{c^2}\frac{\partial^2y}{\partial t^2}-\frac\gamma{\Delta x}\frac{\partial y}{\partial t} = 0 $$
This is the problem. I have a $\Delta x$ term where I am not supposed to.