In my condensed matter class we have seen how to treat the problem of vibration in a lattice in quantum mechanics. After heavy calculation we derive that the number of phonons with a given crystal momentum q and in a band $j$ is
$$ n_j(\textbf{q})=\frac{1}{\exp{\left( \frac{\hbar w_{j\textbf{q}}}{k_BT}\right)}-1} $$
Where $w_{nq}$ is the frequency associated with that phonon. I don't see directly the meaning of it. My interpretation is something like this: we have in our material a huge number of vibrational modes with a specific frequency, therefore the entire lattice will vibrate. We can localize an oscillation on a lattice taking a linear combination of those modes. Suppose that $u_{in}$ is the projection along the i-axis of the displacemente with respect to the Bravais Lattice of the $n$-atom, then we will have:
$$ u_{in} ( \textbf{x},t) = \sum_{j}\int{d^3\textbf{q} \quad c_j(\textbf{q}) \exp\left( i( \textbf{x} \cdot \textbf{q} - w_{j\textbf{q}}t )\right)}. $$
(Question: Is it right to sum also over the band index?)
My idea is that if $n_j(\textbf{q})$ is a high number ($k_b T \propto \hbar w_{j\textbf{q}})$ the the amplitude $ c_j(\textbf{q})$ will be dominant. Is it right? Also if the phonon dispersion relation is given is there a way to compute those $c_j(\textbf{q})$ if our material is at temperature $T$?