# Would a black hole's event horizon split up a hadron into it's constituant quarks? Therefore creating free quarks?

As a thought experiment, say, for the sake of simplicity, we have a meson. This meson, which is traveling near light speed, is traveling towards a black hole. And skirts the event horizon in such a way where the anti-quark ends up inside it's event horizon, but the quark does not. What would happen? Would this create a free quark? That seems like the only logical thing to happen, but I know that would also break color confinement.

• why should the other quark escape, both will fall in. Commented Jul 4, 2023 at 22:40
• @Yukterez, the meson approaches the black hole in such a way where the anti-quark falls into the event horizon, while the quark just barely grazes the event horizon without falling it. The quark has enough velocity to escape the black hole. Commented Jul 4, 2023 at 22:42
• it can't have enough velocity to escape if it grazes the black hole below the photon sphere at r=1.5rs, let alone close to the horizon at r≈1.0rs. Commented Jul 4, 2023 at 22:44
• @Yukterez, The meson is not orbiting the black hole. It is on a hyperbolic trajectory. The photon sphere is the radius where a stable orbit can occur to my knowledge. The meson is not orbiting the black hole. Commented Jul 4, 2023 at 22:48
• It is the radius at which the transversal velocity needs to be the higher than speed of light in order to escape, just like the horizon is the radius where the outward radial velocity needs to be higher than the speed of light. If you graze the black hole your closest approach to it is in transversal motion. If one quark is slightly below and the other slightly above they will stay together since the tidal forces are relatively small at the photon sphere (and mostly even at the horizon, extreme spaghettification only happens close to the singularity where both can't escape anyway). Commented Jul 4, 2023 at 22:56