3
$\begingroup$

So I thought it didn't matter which side of the equation the cosmological constant was one (did it emerge from geometry or the stress energy tensor). However, then I remembered the weak , strong, null, etc energy conditions. Now, if I presume the cosmological constant emerged from the stress energy tensor the this has a direct implications on these inequalities? Or does one say these inequalities are true up to a cosmological constant? What happens if these conditions are violated?

Will be grateful if anyone can shed some light?

$\endgroup$

1 Answer 1

1
+50
$\begingroup$

You are correct that if the cosmological constant is interpreted as being from the stress-energy tensor then it violates the strong energy condition. This is because the strong energy condition can be stated that the pressure plus density of a fluid must be greater than zero. While this holds for non-relativistic matter and radiation it is violated for a cosmological constant as the sum of the pressure and density is zero in that case. There are no adverse consequences to this violation.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.