# Factors determining Saturation Current in Photoelectric effect

Ive understood that the saturation current is the current obtained in a photoelectric experiment when all the photo electrons emitted at the cathode are able to pass through the repulsive space charge and eventually make it at the anode. Although i don't understand the exacts factors on which the saturation current depends on: a) Frequency of incident light? b) Intensity of light?

For example, take the below graph of a photoelectric experiment on the same metal. What can we comment about the frequency and intensity of A B C and why? Thank you!

• What do you think? What role do the frequency and the intensity play in the PE? Sorry, nobody is gonna do your homework for you ;) Commented Mar 15, 2023 at 16:46
• Guess I'm wrong. Commented Mar 15, 2023 at 16:57

Here is a simple rule(not exactly rule but it helps me remember this):

1. In photoelectric effect the intensity decides the number of electron only and more electron emitted more will be the photocurrent

2. The frequency decide only the energy(Kinetic Energy) with which the electrons will be emitted.(means it would require more -ve potential $$V_s$$ to stop the electrons)

So, more is the intensity more will be the photocurrent

a) From graph you can see that stopping potential is same for A and B so their frequency will be same which will be less than frequency of C as for C it require more $$V_s$$ to release the electron as compare to B and C