Is the emitted spectrum is that of a blackbody when the blackbody is in thermal equilibrium with the ambient or with its interior or either? I have came across the following paragraph in Wikipedia

A perfectly insulated enclosure which is in thermal equilibrium internally contains blackbody radiation, and will emit it through a hole made in its wall, provided the hole is small enough to have a negligible effect upon the equilibrium.

So my question is, if I have a blackbody in my room but this black body isn't in equilibrium with with my room. However, it's in equilibrium with its internal structure, let's just imagine I have a perfect glowing blackbody in my room, Does the emitted radiation resembles that of a blackbody?
 A: The internal structure will not be in equilibrium either. It will change in time and so will the radiation output. However emmitted radiation would represent that of BB.
A: Yes, radiation of a blackbody that is not in equilibrium with its environment is still blackbody radiation, with properties of blackbody radiation.
Blackbody need not be in equilibrium with its environment, and its emission need not be equilibrium radiation! In fact usually radiation of a compact finite-sized blackbody can't be, as equilibrium radiation has no macroscopic energy flux in any direction, but blackbody emission produces energy flux from the body away.
The concept of blackbody was not invented as something that exists only when in thermodynamic equilibrium. The premise is that it is the body that absorbs every incoming radiation, and reflects none of its; but at the same time, it also produces its own radiation (emission), and the emitted radiation is characterized by the blackbody temperature and geometry.
The cavity with perfectly reflecting walls with equilibrium radiation inside is not a blackbody, instead the hole that is made in that wall through which radiation escapes, is a realization of blackbody surface (absorbs all incoming radiation, and emits its own blackbody radiation).
