# Why does GPE convert to kinetic energy? [closed]

What is it about GPE that makes it transfer to kinetic energy, why does it do this? What is GPE?

• Two masses attract each other, leading to an acceleration which increases their velocity… Commented Feb 10, 2023 at 14:38
• Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking.
– Community Bot
Commented Feb 10, 2023 at 14:52
• By "GPE" do you mean the Gross–Pitaevskii equation? :P en.wikipedia.org/wiki/Gross%E2%80%93Pitaevskii_equation Commented Feb 10, 2023 at 16:25
• @Quillo No: gravitational potential energy.
– J.G.
Commented Feb 10, 2023 at 16:48

Gravitational Potential Energy (GPE) is the amount of energy an object could have if it were to fall from that height. Thus - provided the gravitational acceleration is constant - gravitational potential energy only depends on mass and how far from the ground ($$h=0$$) the object is suspended, given by $$U=mgh$$. It is transfered to kinetic energy when droped from height h. This kinetic energy can be calculated from the equation $$KE=\frac{1}{2}mv^2$$. If you want to calculate the kinetic energy in terms of the gravitational force $$mg$$, you'll have to apply the Work-Energy Theorem, which states that the net work equals the change in kinetic energy; however, because the kinetic energy is initially $$0$$, it would just be the final kinetic energy, just before the object reaches $$h=0$$. The work is done by multiplying the force ($$mg$$) by the height, $$h$$. Hope this helps.
Consider a ball (of mass $$m$$)falling from a height $$h$$. After some time before the collision, the ball must be at height $$h_{2}$$ which is obviously less than the original height. It is clear from the above observation that: $$mgh > mgh_{2}$$
At the bottom most point(on the ground), GPE is $$0$$ which means all Potential energy had been converted to kinetic energy of the mass. This is why velocity is maximum till the time the object reaches the ground.