# How to find the total current supplied to the circuit?

Recently, I came across a question based on finding electric current of a circuit. Here's the image...

I know, by using the formula $I=V/R$, we can easily calculate the current as $V$ is given and $R$ can be calculated from the diagram. In the book (from where I got the question),

Solve the $R$ (net) by combining the $6 \Omega$ and $2 \Omega$ resistances in parallel, and with both, $1.5 \Omega$ in series and whole parallel with $3 \Omega$.

I didn't get the logic they used. First, I thought of keeping 6, 2 and 1.5 ohm resistors in parallel and with all, the 3 ohm in series. But, that didn't work. Can someone please help me?

• Hi, welcome to physics.SE! I cleaned up the formatting in your answer, have a look at the syntax by clicking "edit" (there's also a section in the site FAQ about formatting math). I also put your picture in directly, which is something you cannot do as a new user (helps prevent spam). Aug 21 '13 at 16:51
• Thanks, for formatting my question. I hope that will help me to get my answer. Aug 21 '13 at 16:57
• Try drawing the circular circuit as a square. It should be pretty clear then why the solution is with 6 & 2 being in parallel and not 6, 2, & 1.5. Aug 21 '13 at 17:09
• I get these kind of problems in my textbook too. Don't know why they test us with such strange diagrams of circuits, when all it is a simple series-parallel combination. Aug 21 '13 at 19:02