# How to find the total current supplied to the circuit?

Recently, I came across a question based on finding electric current of a circuit. Here's the image... I know, by using the formula $I=V/R$, we can easily calculate the current as $V$ is given and $R$ can be calculated from the diagram. In the book (from where I got the question),

Solve the $R$ (net) by combining the $6 \Omega$ and $2 \Omega$ resistances in parallel, and with both, $1.5 \Omega$ in series and whole parallel with $3 \Omega$.

I didn't get the logic they used. First, I thought of keeping 6, 2 and 1.5 ohm resistors in parallel and with all, the 3 ohm in series. But, that didn't work. Can someone please help me?

• Hi, welcome to physics.SE! I cleaned up the formatting in your answer, have a look at the syntax by clicking "edit" (there's also a section in the site FAQ about formatting math). I also put your picture in directly, which is something you cannot do as a new user (helps prevent spam). Aug 21 '13 at 16:51
• Thanks, for formatting my question. I hope that will help me to get my answer. Aug 21 '13 at 16:57
• Try drawing the circular circuit as a square. It should be pretty clear then why the solution is with 6 & 2 being in parallel and not 6, 2, & 1.5. Aug 21 '13 at 17:09
• I get these kind of problems in my textbook too. Don't know why they test us with such strange diagrams of circuits, when all it is a simple series-parallel combination. Aug 21 '13 at 19:02 Now to reform the image, you start out by the positive terminal of the baterry which is connected to the red potential. The 2 and 6 ohm resistances connect the red potential to the black while the 3 ohm connects it direct to the blue. Moreover, the 1.5 ohm connects the black and the blue resistances. Its is depicted below wherein you can easily solve for the net resistance or current.Sorry for the poor diagrams. 