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A well-known example of classical Monte-Carlo method application is Ising model with $S=1/2$.

As I understood, people there widely use it for any kind of magnetic materials following the same idea $$ P_{I\rightarrow f}\propto e^{-\Delta E_{fi}/kT} $$ right?

What does it mean practically? We have an arbitrary Hamiltonian of a large system with two-particles interaction $$ H = H_0 + \sum_{ij} V_{ij}, \quad V_{ij}=I_{ij}\hat{A}_i \hat{A}_j $$ then, we apply sort of mean field approximation and for one subsystem (spin) one can write $$ H_i \approx H_0^{(i)} + \sum_{j} I_{ij} \langle A_j\rangle \hat{A}_i $$ where $\langle A_j \rangle$ are just numbers stored somewhere from the previous calculations.

Ok then, according to the method, we pick up a random $i$ and try to update it's state. In order to do that we find all eigenvalues and eigenstates of $H_i$, i.e. $$ H_i: \quad set~of~\{E_k^{(i)},\Psi_k^{(i)}\} $$ At this stage I do not know what is the correct way of dealing with it using local update strategy

  1. Pick up a new state $\Psi_m$ for $i$-subsystem by random choice from the subset of $\{E_k,\Psi_k\}$ with weights $e^{- E_k/kT}$ and store $\langle A_j \rangle = \langle \Psi_m | A | \Psi_m \rangle$ for further calculations
  2. Perform a transition from some initial (previous) state $\Psi_h$ to any of available states $\{E_k, \Psi_k\}$ with probability $e^{-(E_m-E_h)/kT}$ (where $E_h$ is recalculated using the present Hamiltonian on the old $\Psi_h$). And then store $\langle A_j \rangle = \langle \Psi_m | A | \Psi_m \rangle$ as well as a new state $\Psi_m$ for the further calculations

The second (2) approach looks more sophisticated for me and kinda feels more natural due to the transitions caused by the thermal fluctuations, not clear how to implement it.

Due to the lack of knowledge I followed (1) a long time ago and tried it for the ferrimagnetically bonded cubic spin-system with (L=2, S=2) and (L=0, S=3/2). It reproduced quite well the phase transition, hysteresis loop and etc. But I still have doubts in this regard, if this procedure (1) is statistically correct.

I hope some brainy Monte-Carlo guys here can clarify it a bit for me.

PS: Some extra details

For the simplicity I tested it on a simple cubic spin system with S=3/2 $$ H = H_{anisotropy} + H_{dipole-dipole} + H_{exchange} $$

img

it forms a multidomain state, similar to Ref, where they managed to form magnetic-domains using Classical Monte-Carlo.

It looks right for now...

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  • $\begingroup$ I think I found something relevant in ref page 7 (bottom) <<When this is repeated the Markov process generates a Markov chain of states, containing the states we wish to sample from when making our measurements. This process is necessary as we cannot simply choose a state at random and use the Boltzmann distribution to decide whether we should use it or not: almost all states would be rejected due to the exponentially decreasing probability in the Boltzmann distribution>> $\endgroup$ Commented Jan 4, 2023 at 19:20
  • $\begingroup$ It looks like nobody does something like this, because each time when we diagonalize the Hamiltonian we change the basis and the quantization axis as well, and the previous state is lost $\endgroup$ Commented Jan 4, 2023 at 19:40

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