# If finite number of photons leave a source, would certain solid angles be dark?

If a light source emits light, and due to the inverse square law “energy flux” (number of photons passing through a given area) decreases rapidly. Then at some distance away from the source there would be certain solid angles with 0 photons passing through, right?

I am imagining a shrapnel explosion where the shrapnels are photons.

many images depicting the inverse square law uses this format:

I can’t help but get the impression that after a certain distance there will be some squares with 0 arrows passing through.

• I guess it becomes a question of probability. You have less and less chance of detecting a photon in a certain solid angle, but never zero. Commented Dec 28, 2022 at 9:33
• You are right. Anything more specific you are interested in? @dan-ros: Yes, the probability (or the photon detection rate) gets lower with distance and when you actually do a measurement over a certain time interval there will be squares with zero photons measured. Commented Dec 28, 2022 at 9:36
• The question Photons from stars--how do they fill in such large angular distances? is closely related if not exactly the same. Also see Some doubts about photons. Commented Dec 28, 2022 at 17:49
• @JohnRennie provides very good answers in the cited answers. He says one thing that needs emphasizing: light is neither a wave nor a particle. It's something else entirely, something that has no metaphor or analog in the macroscopic world. You might read "sometimes a wave; sometimes a particle". That gives the wrong idea. It's too simple, and needs explaining to be correct. Light is neither. Commented Dec 28, 2022 at 19:34