If finite number of photons leave a source, would certain solid angles be dark? If a light source emits light, and due to the inverse square law “energy flux” (number of photons passing through a given area) decreases rapidly. Then at some distance away from the source there would be certain solid angles with 0 photons passing through, right?
I am imagining a shrapnel explosion where the shrapnels are photons.
many images depicting the inverse square law uses this format:

I can’t help but get the impression that after a certain distance there will be some squares with 0 arrows passing through.
 A: There are not many ways to generate EM radiation. Mostly we observe the emission of photons from excited electrons. And very often this takes the form of thermal radiation. For astronomy, there is also radiation produced by the powerful magnetic fields of stars and the electrons deflected in them (Lorentz force or better EM induction).
The fact is that it is always photons - of the most varied energy content - that are emitted and that we also receive as such. While this is not so obvious for close sources, for very distant sources this is the only way to investigate the source. With extremely long exposure times and the registration of single photons, filtered out from a noise of photons until an image of the star emerges.

Then at some distance away from the source there would be certain solid angles with 0 photons passing through, right?

The further away the source and the less radiative it is, the less often a photon will strike a finite surface in a certain period of time. What helps are long-term observations and the enlargement of the detection area.
The whole thing is quite intuitive and I almost suspect that your question was aimed at something deeper.
