In this question, the problem of finding matrix representations for a set of Grassmann variables is discussed.

How can this representation be used in Berezin integrals or Grassmann derivatives? Can one define a Berezin integral as a linear transformation acting on these matrix representations as a superoperator?

For a set of $N$ generators $\theta_n$ and a given representation \begin{equation} \theta_n = (\bigotimes_{1}^{n-1} \sigma_z) \otimes \sigma_- \otimes (\bigotimes_{n+1}^{N} 1), \end{equation} I thought of the map \begin{equation} \theta_n \rightarrow ((\bigotimes_{1}^n \sigma_z) \otimes (\bigotimes_{n+1}^N 1)) [\theta_n, (\bigotimes_{1}^{n-1} \sigma_z \otimes \sigma_+ \otimes (\bigotimes_{n+1}^N 1)], \end{equation} where the brackets are a commutator, which seems to respect the main features of the Berezin integral of a Grassmann variable $\theta_n$, but I don't know if it satisfies all of them.



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