I know the products of the annihilation, but I don't know how much energy each particle has or gets. For example I know that 1876 MeV is released for each annihilation. Now, this energy is distributed among a number of pions, so how much energy does each pion get ?
Also, this energy is distributed between kinetic and rest mass energy, how is it distributed ? and where does the kinetic energy go when the pions decay ?
And what about the electron we get from the muon decay ? how much energy does it get and is this energy easy to obtain or it will just fly away similar to a neutrino ? I mean how far will the electron go in a medium until its energy is absorbed ?
EDIT : I asked this question because I am confused where the kinetic energy of the particles go. Firstly, the neutral pion gets 390 MeV total energy, of which 135 MeV is the rest mass energy and 255 MeV is its kinetic energy. As some people said before, the decay of the neutral pion result in 2 gamma rays each with 67 MeV, which is only the rest mass energy over two, so where did the kinetic energy go ? shouldn't the pion have resulted in 2 gamma rays with 195 MeV each considering energy conservation ?
Secondly, the charged pions. as well as the neutral pion, they get 395 MeV of energy too. When they decay, the product is a muon and a neutrino which I dont know how the energy is distributed here. Then the muon decays into an electron or a positron and 2 more neutrinos which I also don't know how much energy they get.
Thirdly, the kinetic energy of the charged pions. How do the charged pions lose their kinetic energy ? and what will happen if the charged pion decayed before losing its kinetic energy ?
All these three questions haven't been discussed in the related question, and thus this is not a duplicate.