How is the energy distributed in a proton-antiprotion annihilation? I know the products of the annihilation, but I don't know how much energy each particle has or gets. For example I know that 1876 MeV is released for each annihilation. Now, this energy is distributed among a number of pions, so how much energy does each pion get ?
Also, this energy is distributed between kinetic and rest mass energy, how is it distributed ? and where does the kinetic energy go when the pions decay ?
And what about the electron we get from the muon decay ? how much energy does it get and is this energy easy to obtain or it will just fly away similar to a neutrino ? I mean how far will the electron go in a medium until its energy is absorbed ?
EDIT :
I asked this question because I am confused where the kinetic energy of the particles go. Firstly, the neutral pion gets 390 MeV total energy, of which 135 MeV is the rest mass energy and 255 MeV is its kinetic energy. As some people said before, the decay of the neutral pion result in 2 gamma rays each with 67 MeV, which is only the  rest mass energy over two, so where did the kinetic energy go ? shouldn't the pion have resulted in 2 gamma rays with 195 MeV each considering energy conservation ?
Secondly, the charged pions. as well as the neutral pion, they get 395 MeV of energy too. When they decay, the product is a muon and a neutrino which I dont know how the energy is distributed here. Then the muon decays into an electron or a positron and 2 more neutrinos which I also don't know how much energy they get.
Thirdly, the kinetic energy of the charged pions. How do the charged pions lose their kinetic energy ? and what will happen if the charged pion decayed before losing its kinetic energy ?
All these three questions haven't been discussed in the related question, and thus this is not a duplicate.
 A: 
: I asked this question because I am confused where the kinetic energy of the particles go. Firstly, the neutral pion gets 390 MeV total energy, of which 135 MeV is the rest mass energy and 255 MeV is its kinetic energy.

We are talking of average numbers. On average there are five pions, on average they each have 390 MeV, on average ...

As some people said before, the decay of the neutral pion result in 2 gamma rays each with 67 MeV, which is only the rest mass energy over two, so where did the kinetic energy go ? shouldn't the pion have resulted in 2 gamma rays with 195 MeV each considering energy conservation ?

The 67 MeV is the energy at the center of mass system of the pi0. As the pi0 is in the lab, you are right the two gamma rays will on the average have 195 MeV each.

Secondly, the charged pions. as well as the neutral pion, they get 395 MeV of energy too. When they decay, the product is a muon and 2 neutrinos which I dont know how the energy is distributed here. 

Pions decay into two bodies, they go  to a muon and a muon anti/neutrino ( to conserve lepton number). A two body decay and at the center of mass of the pion the neutrino gets most of the kinetic energy. What happens in the lab will depend on the angular distribution of the decay versus the direction of motion of the pion. 

Then the muon decays into an electron or a positron and 2 more neutrinos which I also don't know how much energy they get.

These are three body decays and their distribution can be found in the literature of some decades back . 

Thirdly, the kinetic energy of the charged pions. How do the charged pions lose their kinetic energy ?

Charged particles interact with the  field of the molecules of the matter they go through and lose a bit of kinetic energy by ionizing them, that is why we can see their tracks in bubble chamber pictures. In dense matter they lose energy fast.
Have a look at this lecture.

and what will happen if the charged pion decayed before losing its kinetic energy ?

Here is a pion stopping and going into a muon etc. In flight most of the momentum gets carried on by the muon.
It will decay in flight into a muon and a neutrino which will share all the energy ( mass and kinetic) of the pion.
I think you are trying to get in a nutshell information that needs a course in elementary particle physics. It cannot be done. Knowledge cannot be transmitted by hand waving words. To understand such matters problems must be solved and time spent in reading relevant material. Students who sit in courses are not stupid, they are interested in learning this stuff that you are trying to absorb by osmosis. It cannot be done. If you need details you have to spend the time necessary to understand details.
