In the observer's frame the events A and B are simultanous ($\Delta t = 0$) and are separated by $\Delta x$
We can get the corresponding time between events in the car frame using the Lorentz Transformation $\Delta t' = \gamma(\Delta t - \frac{V\Delta x}{c^2})$ and so
$\Delta t' = -\gamma\frac{V\Delta x}{c^2}$. From this equation the car always observes B happening before A hence the negative sign.
Suppose that the car at t=0 is at A or before A. And suppose that B is almost infinitely seperated (millions of light years away). Even though A is super close to the car and B is super far away from the car the equation $\Delta t' = -\gamma\frac{V\Delta x}{c^2}$. Tells us that if $\Delta x$ is super-large then B happens waaay before A. How is that possible what is the intuition behind this ?
The question is why even tho car is going toward both A and B, B has to happen first not A ? Physically what is the intuition behind this
*I understand that this is not about light reaching the observer as some answers assume that I do