Potential at Equatorial point of dipole is given 0 in my book(after putting angle = π/2 and cos(π/2) = 0 in formulae
V = (K p cos(x)/r2)
x = angle made my direction vector of point where potential is to be determined with center of dipole
p = dipole moment
R = distance between two charges
I am confused that potential at a point is work done per unit charge in bringing from infinity to that point and suppose if I bring a test charge along the axial line and stops at a point lying on Equatorial line then I have to do work since Electric field was there due to dipole.
Can you please explain me this?