The WKB approximation provides an approximative solution to the one-dimensional, time-independent Schrödinger equation
$$ -\frac{\hbar^{2}}{2m} \frac{d^{2}}{dx^{2}} \Psi(x) +V(x)\Psi(x)=E\Psi (x)$$
under the assumption that the potential $V(x)$ 'varies slowly' on the scale of the wavelength $\lambda$.
Can this sloppy assumption be turned in precise mathematical condition?
My unsuccessful attempt to express it as the condition $\frac{\Delta V}{\Delta \lambda} \ll 1 $ runs into troubles for dimensional reasons, since $V$ doesn’t have the dimension of a length.
Even more confusing in this approach above is that $\Delta V = V'(\xi) \Delta \lambda $ for $\xi \in [\lambda_0, \lambda_0 + \Delta \lambda] $ by the mean value theorem would lead to $V'(\xi) \ll 1$.
But the derivative $V'(x)$ of the potential is not necessarily almost zero globally, so something is wrong in my considerations.
Could somebody explain how the 'slow variation' of $V(X)$ on wavelength scale of $\lambda$ should be expressed mathematically here? My intention is to prove that if this 'slow variation' assumption is posed, then the WKB approximation approaches a solution. But in order to do it, I need to translate the condition on 'slow variation' into a strict mathematical form.