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Is it possible to calculate the refractive index of a material for $wavelength = 546.07 \ nm$, knowing that the dispersion of a prism made of this material is $3.44 \times 10^{-5} \ nm^{-1}$, and that the refractive index for the yellow line, $577.96 \ nm$ wavelength, is $1.5171$ ?

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    $\begingroup$ try this en.wikipedia.org/wiki/Fresnel_equations $\endgroup$ Sep 23 at 18:18
  • $\begingroup$ @AslanMonahov This is not about the Fresnel equation, it is about the definition of the coefficient of dispersion. $\endgroup$ Sep 23 at 21:53
  • $\begingroup$ Hint: The index of refraction is a function of the wavelength $n(\lambda)$, the (coefficient of) dispersion is given by $\frac{dn}{d\lambda}$. Now you can Taylor expand $n(\lambda)$ to the first order to approximate $n(\lambda + \Delta \lambda)$. Note that it should say, that the dispersion at a wavelength has a certain value – the dispersion is typically not constant. $\endgroup$ Sep 23 at 21:56

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