A faster-than-$c$ group velocity is a case where a medium (such as a solid, gas or plasma) has been set up in a special state.
Consider the following comparison.
Suppose I arrange a set of dominoes to fall over, one after the other. The usual procedure is to line them up and then push one over, and it falls against the next, which topples onto the next, and so on.
Let's say the dominoes are separated by 2 cm and each takes $0.2$ s to fall over and push the next. Then the 'wave' of toppling dominoes travels at the speed $2/0.2 = 10 $ cm/s.
But now suppose I set them up a different way. I place them on a set of little platforms, like the keys on a piano, separated by 2 cm as before, and arrange that each platform can tip. Then I attach a mechanism to all these platforms. Now I can have some fun. I could, for example, make all the platforms tip at the same time. Or I could make them tip over in sequence, with 10 millisecond between each one and its neighbour. So now the dominoes will fall over one after the other, and the wave of falling dominoes travels at the speed $2/0.01 = 200$ cm/s. So now I have a wave travelling at twenty times the "speed of domino"!
With light in a specially prepared plasma you can get similar effects. The leading edge of a 'priming' pulse runs through a plasma at some speed less than $c$, and sets up the plasma so that it is ready to react in such a way that each part of the plasma does something (makes an electric field or a concentration of charge), but the first part to be stimulated does it more slowly than the last part. (This could happen, for example, when the priming pulse gets amplified as it goes).
For example, suppose the two ends are separated by 3 metres, and let the priming pulse travel from left to right. Then the left end gets stimulated at time $t=0$ and the right end gets stimulated at time $t = 3/c = 10$ ns. Suppose also that the left end takes about 11 ns to build up a substantial reaction, and the right end takes 2 ns to build up a substantial reaction. Suppose similarly that places in between take times in between. Then some larger disturbance will appear at the left at $t=11$ ns, and some such disturbance will appear at the right at $t=12$ ns, and overall you will see a disturbance running through the plasma such that it travels 3 metres in 1 nanosecond. Hence its speed is $(3 {\rm metres})/(1 {\rm ns}) = 3 \times 10^9$ m/s which is $10c$.
This is perfectly possible.
The information travelled at the speed $c$ (or less) when the plasma was set up. The reaction then happened as described.
One way to see that this fast-moving disturbance does not constitute a message is to ask what would happen if someone interfered with the build-up of the reaction at the left hand end at the time, say, $t = 10.1$ ns. Would this prevent the fast-travelling disturbance? The answer is no. The effect at the right (charge movement and electric field) would still happen just the same.