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Let's suppose that you have a pot of water inside a vacuum chamber and one inside of a regular chamber. All else equal.

Let's suppose that heat is being transferred from outside of the chambers into the chambers. Which pot of water will boil first?


Let's now suppose the reverse.

Let's suppose that heat is being transferred from inside the chamber to ouside.

Which pot of water will turn into ice first.

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    $\begingroup$ FYI: If there's an open container of water in a chamber, then it isn't really a vacuum chamber. If it's got a vacuum pump, and you switch the pump on, then you'll have a low-pressure water-vapor chamber until all of the water has boiled away. If you can supply enough heat to keep the temperature of the water at 20C, then the water will boil when the pressure gets down to about 2.3% of standard atmospheric pressure, and the pressure won't get any lower until the liquid water is all gone. en.wikipedia.org/wiki/Vapour_pressure_of_water $\endgroup$ Commented Aug 26, 2022 at 2:19

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The question is impossible to answer without additional information. Even assuming a sealed subordinate container with a volume of air and a volume of water (see Solomon Slow's comment), information about the heating method is needed. If we heat very slowly, such that everything in the insulated chamber is at thermal equilibrium with everything else in the chamber, the small addition of the heat capacity of air will make that chamber rise in temperature more slowly. If we heat rapidly, far from equilibrium, we might find the vacuum chamber's water boiling slightly faster (for instance: we shine a 63 GHz laser at the container), or we might find the air chamber's water boiling much faster (for instance: both chambers are convection ovens, but the vacuum chamber has no air to convect heat to the container, so the heating elements stay somewhat hotter and the water container remains cool for longer).

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