I have a doubt that for an ideal (massless)spring if apply an constant force over it until equilibrium the energy stored over it is ( kx^2)/2 and the work done by force is kx^2 so where the half of the energy gone Also in thermodynamics work done on the gas when a gas is compressed due to a constant pressure over it is Pext(Vf -Vi) irreversibly,why here all the external work is considered Both question are interrelated and contradictory to each other I have an inside feeling that the work in second case should not be be equal to Pext(Vf -Vi) as initially the opposing force is less than that of external one
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1$\begingroup$ Does this answer your question? Mass dropped on a spring $\endgroup$– ChemomechanicsAug 9, 2022 at 4:36
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$\begingroup$ See also 1, 2, 3, 4, 5, 6, 7, 8. This previous answer contains a long list of such factor-of-two questions. $\endgroup$– ChemomechanicsAug 9, 2022 at 4:43
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