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If the non-constant acceleration is multiplied by a constant (on every point), would the total path also be multiplied by the same constant over the same time? Both starting and ending speeds are zero at that time period (if that makes a difference, the a(t) is not defined as a function, but it looks somewhat like a sinusoid with t(start)=0 and t(end)=2π)

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    – Community Bot
    Aug 6 at 15:49

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If a(t) is multiplied by c the integral over a(t) and c*a(t) you can easily compare, the same with again taking the integral. So what is the problem?

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