I've learned that current will flow to bring the potential of both ends of a wire to the same value if there is a difference in potential between them.
Consider a cell of emf, , and negligible internal resistence.Then, suppose I connect one end conducting wire of negligible resistence to the positive terminal of the battery while leaving the other end free.This would create a potential difference accross the ends of the wire(initial potential at the ends is equal to zero).
IS THE CURRENT (flow of charge) GOING TO FLOW (with charge entering cell)?
WHAT I THOUGHT WOULD HAPPEN:
My understanding is that the positive terminal will attract electrons, and as electrons move from the wire to the terminal, the potential of that terminal will decrease ( this flow is happening since the terminal is in contact with the wire and so electron can get on the termminal).
Next, due to the Electromotive force mechanism (which isn't actually a force) in the cell , the electron will then be moved (kind of ) to the negative terminal of the cell, lowering the potential of the negative terminal in order maintain the initial potential at positive terminal.
I'm unsure of what happen next.I believe that until a static condition is reached, this process will continue.
Was my thinking correct?
Would something like this actually occur? If it does, won't disconnecting the wire after sometime change the emf of the cell?
Note--- I believe I must be mistaken after giving it some additional thought, but what is correct in that case?
I simply want to know what is actually going on and what function the cell's EMF and chemical reaction are performing.
I would value a thoughtful response that could help me figure things out.