I've just come across Krasinsky and Brumberg's paper that claims, from an analysis of radiometric measurements, that the astronomical unit (earth-sun distance) is increasing at the rate:
$$\frac{d}{dt}AU = 15 \pm 4 \ m/yr.$$
If one assumes that the Solar system is expanding with the Universe then the Earth-Sun distance is given by:
$$R = R_0 \ a(t),$$
where $R_0$ is the present Earth-Sun distance and $a(t)$ is the scale factor.
From the definition of the Hubble parameter we have:
$$\frac{da/dt}{a} = H.$$
Therefore
$$dR = R_0 da$$
$$dR = R_0 \ a \ H \ dt$$
At the present time $H=H_0$ and $a=1$ so that:
$$dR/dt = R_0 H_0.$$
If I use $R_0=1.49\times10^{11}m$, $H_0=1/13.77\times10^9 yr^{-1}$ and $dt=1yr$ I find:
$$dR/dt = 1.49\times10^{11} \cdot (1/13.77\times10^9)$$
$$dR/dt = 10.8 \ m/yr.$$
Thus the rate of increase of the AU unit might well be explained if the Solar system is expanding like the Universe.
PS Krasinsky seems to dismiss the possibility that his results are explained by cosmic expansion because he somehow derives the rate $dR/dt = 1 \ km/yr$ under such an hypothesis. I can't see how he got that result.