I did some digging around and I found that solar storms can quite significantly erode the surface of the moon. From NASA's website, they say:
"We found that when this massive cloud of plasma strikes the moon, it acts like a sandblaster and easily removes volatile material from the surface," said William Farrell, DREAM team lead at NASA Goddard. "The model predicts 100 to 200 tons of lunar material – the equivalent of 10 dump truck loads – could be stripped off the lunar surface during the typical 2-day passage of a CME."
I also did a simple calculation to test how significant such an effect could be:
The luminosity of the sun is typically known to be $L_{\odot}$. A solar flare could increase its luminosity by $\Delta L$ such that the total luminosity from a solar storm is on average $L_{\odot} + \Delta L$ which will be distributed on a sphere of radius $R$, the distance between the Moon and Sun. For every photon, $p = E/c$ which means $P = I/c$ where $P$ is pressure and $I$ is energy density per unit time. Hence, the pressure on a dust particle on the moon is
$$P = \frac{I}{c} = \frac{L_{\odot} + \Delta L}{4\pi R^2 c}.$$
Consider a dust particle of density $\rho$ and radius $r$. The force from radiation on this particle will hence be
$$F_{\text{radiation}} = PA = \frac{(L_{\odot} + \Delta L) \pi r^2}{4\pi R^2 c}$$
The gravitational attraction between the dust particle and moon is given by Newton's law:
$$F_{\text{gravitation}} = \frac{Gm_{\text{moon}} (\frac{4}{3}\pi r^3 \rho)}{r_{\text{moon}}^2}.$$
So, let's create a dimensionless parameter $\alpha$:
$$\alpha = \frac{F_{\text{radiation}}}{F_{\text{gravitation}}} = \frac{(L_{\odot} + \Delta L) r_{\text{moon}}^2}{16\pi G \rho c R^2 r m_{\text{moon}}}$$
If $\alpha$ is around $1$, we can say the forces are within comparable magnitude.
Plugging in values when taking $\Delta L = 0$:
$$\begin{align*}
L_{\odot} &= 3.8\times 10^{26}\;\mathrm{W} \\
r_{\text{moon}} &= 1737400\;\mathrm{m} \\
G &= 6.67 \times 10^{-11}\;\mathrm{m^3 kg s^{-2}} \\
\rho &= 3340 \;\mathrm{kg/m^3} \\
c &= 3\times 10^8 \;\mathrm{m/s} \\
R &= 1.52\times 10^{11}\;\mathrm{m} \\
r &= 10^{-6}\;\mathrm{m}
\end{align*}$$
gives us the value of $\alpha \approx 0.0067$. Depending on the value of $\Delta L$, the effects of solar radiation could be even greater.
In conclusion, the effects of solar radiation are not negligible, but probably more exaggerated in For All Mankind.