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A spectral line is determined by a particular transition in an atom or molecule. In reality, this line isn't infinitely sharp, but has a small distribution about the resonance frequency as a result of a few things. This distribution will have a lineshape, e.g., Gaussian, Lorenztian, Voigt, etc. My first question is: is each spectral line, corresponding to a unique transition within an atom or molecule, going to have a unique lineshape?

My initial reasoning leads me to say yes. Given that lifetime broadening (which gives a spectral line its natural width) concerns the energy uncertainty ΔE of the transition, and this ΔE is different for every transition in a given atom/molecule, then the lifetime broadening should be different and thus the shape as well. The other sources of broadening, like doppler or collision broadening, should apply uniformly. Is all of this correct?

Secondly, I'd like to ask about isotopes: different isotopes will have different, unique spectra compared to each other (even if the difference is subtle). Will the same transition in each isotope have the same lineshape? In other words, will a transition in isotope 1 have the same lineshape as the same transition in isotope 2? (By "the same", I mean that even though the frequency / energy gap is slightly different, it's still the same transition between particular orbitals).

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    $\begingroup$ Could you specify what you mean by 'line shape'? Like do you mean the width and the curvature of the spectral lines or? $\endgroup$ Jun 8, 2022 at 20:48
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    $\begingroup$ @DiracDeltaYeah the line position, maximum height and half-width en.wikipedia.org/wiki/Spectral_line_shape $\endgroup$
    – compp
    Jun 8, 2022 at 20:50
  • $\begingroup$ Lorentzian is why you get from a finite lifetime, so it’s the natural Lineshape. Gaussian is from broadening effects like collisional, thermal, Doppler etc. Voigt is just the convolution between the two. $\endgroup$
    – SuperCiocia
    Jun 13, 2022 at 22:07
  • $\begingroup$ @SuperCiocia yes, that I understand, thank you :) $\endgroup$
    – compp
    Jun 13, 2022 at 22:15

1 Answer 1

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A lot of questions, but since they are related, we go on:

A spectral line is determined by a particular transition in an atom or molecule. In reality, this line isn't infinitely sharp, but has a small distribution about the resonance frequency as a result of a few things. This distribution will have a lineshape, e.g., Gaussian, Lorenztian, Voigt, etc. My first question is: is each spectral line, corresponding to a unique transition within an atom or molecule, going to have a unique lineshape?

Unique, maybe no. Remember we have also measurement accuracies in play. Few popular shapes, yes.

A lot of spectral lines (e.g. the famous sodium doublet at 589nm) are in fact multiplets and this was discovered after the equipment and measurement techniques evolved enough precision to distinguish them.

Multiplets have their intrinsic intensity ratios between the constituent lines, so yes, this can count as different shapes.

My initial reasoning leads me to say yes. Given that lifetime broadening (which gives a spectral line its natural width) concerns the energy uncertainty ΔE of the transition, and this ΔE is different for every transition in a given atom/molecule, then the lifetime broadening should be different and thus the shape as well. The other sources of broadening, like doppler or collision broadening, should apply uniformly. Is all of this correct?

I don't see flaws there.

Secondly, I'd like to ask about isotopes: different isotopes will have different, unique spectra compared to each other (even if the difference is subtle). Will the same transition in each isotope have the same lineshape? In other words, will a transition in isotope 1 have the same lineshape as the same transition in isotope 2? (By "the same", I mean that even though the frequency / energy gap is slightly different, it's still the same transition between particular orbitals).

The above consideration about the lifetime broadening still holds. Since the frequency differences are this much subtle, the lifetime broadening differences will be correspondingly subtle, but in theory will be there.

Then again, see the hyperfine structure - isotopes do have different nuclear spin, different nuclear magnetic momentum and as an effect - different hyperfine splitting.

Depending on your wavelength resolution, this may also count for different "shape" of a line or for completely different lines.


Now I see you also talk about molecules in the title of your question.

With molecules in a gas phase, everything becomes a multiplet by adding and subtracting vibrational and rotational transition energies to/from the electron transition energy.

A beautiful example e.g. here: https://opentextbc.ca/universityphysicsv3openstax/chapter/molecular-spectra/


a comment from @Landak with some good remarks:

This is a great answer, but it might also be an idea to mention the fact that Lorentzian shapes arise as the Fourier transform of an exponential damped sinusoid (i.e. natural lifetime decay) and Gaussian lineshapes arise if diffusion dominates. The situation is more complex if the experimental imperfections (or natural properties of the material studied) are considered – for an obvious but different example think of the homogeneity of the magnetic field in NMR or EPR spectroscopy where the lineshape observed can be completely changed by it.

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    $\begingroup$ Edit: added about the molecular spectra that have their own multiplet flora $\endgroup$
    – fraxinus
    Jun 9, 2022 at 7:35
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    $\begingroup$ This is a great answer, but it might also be an idea to mention the fact that Lorentzian shapes arise as the Fourier transform of an exponential damped sinusoid (i.e. natural lifetime decay) and Gaussian lineshapes arise if diffusion dominates. The situation is more complex if the experimental imperfections (or natural properties of the material studied) are considered – for an obvious but different example think of the homogeneity of the magnetic field in NMR or EPR spectroscopy where the lineshape observed can be completely changed by it. $\endgroup$
    – Landak
    Jun 9, 2022 at 9:26
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    $\begingroup$ @Landak if you don't mind, I'll paste your remarks to the answer. They are pretty good addition and the comments are not a safe place for them. $\endgroup$
    – fraxinus
    Jun 9, 2022 at 10:00
  • $\begingroup$ @Landak thank you as well! really appreciate the extra detail $\endgroup$
    – compp
    Jun 9, 2022 at 16:19
  • $\begingroup$ @fraxinus the molecular spectra addition is gorgeous. This is why I love asking questions on here $\endgroup$
    – compp
    Jun 9, 2022 at 16:22

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