# Velocity of ball sliding on bowl. Need to understand why vertical velocity of bowl is 0 and ball is not

There's this ball which falls from height $$h$$ into a bowl, there are $$3$$ named points on the bowl, $$A$$ the first upper point the ball hits, $$C$$ same as $$A$$ but on the opposite direction, and $$B$$ which is at the bottom of the bowl.
There's no friction.
In the horizontal axis, there's momentum conservation because no external forces (also there's energy conservation, all forces are conservative, no friction...).
I understand that at points $$A$$ and $$C$$ the velocities are equal since both objects are moving together (horizontally only), and at point $$B$$ they're not.
But how come the answer when finding the velocities at point C is as follows:
(also, initial horizontal momentum is zero, since both ball and bowl are not moving horizontally)
(in horizontal axis) $$P_i = P_f$$ ($$i= initial$$, $$f= final$$....this is because momentum conservation)
$$(m+M)u = 0$$ (both velocities are equal horizontally)
then the conclusion is that the bowl's and the ball's velocity is $$0$$
Afterwards they used energy conservation doing $$(E_i = E_f)$$:
$$mg(h+R) = mgR + \frac{1}{2}mu^2$$ (but this u is for the ball's velocity, I assume vertical velocity, since the horizontal is $$0$$ as mentioned above)

if both velocities are equal at point $$C$$ then what's the assumption the bowl's velocity vertically is $$0$$ and the ball's is not (as used in the energy part. Obviously the ball is not since it's moving on the bowl)? could someone please help me understand what I'm missing \ misunderstanding? I can't figure out what I'm missing in the answer for which they only used the velocity of the ball in the energy conservation equation
(*still didn't learn center of mass in here, so can't depend on it)
a drawing I made to help understand where each point is... • Are you asking why you can assume the vertical velocity of the bowl at point C is zero? The fact you know all the momentum is vertical and the fact that the movement of the bowl is constrained in the vertical direction by the table seems enough to me. (Also, we are we assuming this bowl us curved on the outside as drawn? Or is that curve just the inside and the outside is actually flat bottom so can't rock?) May 27, 2022 at 18:45
• I mean, isn't it enough just to know that $v_y = 0$? It's like problems where there are rollers on horizontal or vertical guide rails. You know certain values in certain directions are not allowed so you fix those at zero. It's not unlike how you might use a cosine or sine to relate one the $v_x$ to $v_y$ on a guide rail that is being held at an angle. I would be a lot more confused about how you know the entry of the ball doesn't cause a bounce. May 27, 2022 at 19:06
• Well, you would know there is table there (I'm assuming that's specified somewhere in the problem) and you would probably assume that the ball doesn't smash through the bowl or the table. May 27, 2022 at 19:07
• I don't know how to tell if it bounces or not though. I assume anything other than a perfect half circle where the ball doesn't follow the tangent upon entry causes a bounce but I don't know how you differentiate that from the normal force pointing away from the surface while it is in the arc vs just entering the arc. May 27, 2022 at 19:13
• I made a question about bounce here: physics.stackexchange.com/questions/710898/… May 27, 2022 at 19:29