# Does this relativistic generalization of the Schrodinger equation make sense? [duplicate]

So I'm aware that the correct relativistic approach to quantum mechanics is through quantum fields, but I'm still interested in the question that follows.

We know the Schrodinger equation in free space in $$d=1$$ is as follows: $$i\hbar \partial_t \psi=-\frac{\hbar^2}{2m}\partial_{xx}\psi.$$ Classically, the relativistic generalization of kinetic energy is $$E=\sqrt{m^2c^4+p^2c^2}-mc^2.$$ What happens if we expand up to order $$4$$ in $$p/mc$$, and substitute $$p\to -i\hbar\partial_x$$ to write the little bit more relativistic Schrodinger equation:

$$i\hbar\partial_t\psi=-\frac{\hbar^2}{2m}\partial_{xx}\psi-\frac{\hbar^4}{8m^3c^2}\partial_{xxxx}\psi,$$ neglecting the higher order contributions. Is this new equation physically meaningful? We still have conservation of probability because the hamiltonian is still hermitian. I ask my question again: is this approach physically useful?