In the given figure,we connect three cells of different emf which are $V_1,V_2,V_3$ with a resistance $R$ in the first loop. Now suppose we emit current $I$ from $V_1$. $I$ gets divided into $I_1$ and $I_2$ with $I_1$ flowing through $V_2$ and $I_2$ through $V_3$.
Now if i apply KVL in the second loop where their are only voltage sources $V_2$ and $V_3$, we will get $-V_3+V_2=0$ or $V_2=V_3$ but that's a contradiction since we took the $3$ cells of different emfs. Where am i making a mistake? Is KVL not applicable to this loop? Or did i make a mistake in dividing the currents? Kindly correct me.
ADDENUM: As per the answers,i came to the conclusion that it is impossible to make such a circuit. But the following is an old problem from an olympiad.(A previous post of mine was closed alleging it to be a homework problem even though i was making sure if the problem was wrong or not)
All the diodes are ideal here so that should mean there is no potential drop and they are just behaving as a normal wire which is the situation i have in the original question,then how is the circuit they made even possible to exist? As per the above answers,if my given circuit cant exist,then so can't the circuit in this problem.