7
$\begingroup$

Background: A scalar field on the unit sphere can be expanded in spherical harmonics, see e.g. this. I am wondering if there is a related concept for vector fields and, in general, for any kind of tensor field. Which is the basic idea/intuition behind the extension from scalar fields to tensor ones?

This concept seems related to the multipole expansion for vector fields, but it's not exactly the same concept. Moreover, I know that something called vector spherical harmonics exists and I am quite sure that this is the concept I have in mind for the case of vectors (see the example below and this question). For the rank-2 case, I do not understand if the notion of spherical tensor provides a solution to the question.

Question: Given my doubts reported above, the definition of Wikipedia of Vector spherical harmonics seems quite arbitrary to me: I am not able to grasp the "rationale" behind it. Which is the general concept we have to use when moving from scalar fields to tensor ones?

Example: imagine having a field theory defined on the sphere (the base manifold is the unit sphere) and that we want to expand the energy-momentum tensor in series: we should use a proper basis of orthogonal "matrix" fields on the sphere. The same if we have a fluid flowing on the surface of a sphere: we need a set of vector fields that live on the sphere that are "complete" and "orthogonal". I expect that this set will be "countable" (like usual spherical harmonics for scalars) because the sphere is a compact manifold.

$\endgroup$

1 Answer 1

2
$\begingroup$

The concept of spherical harmonics and even hyperspherical harmonics (in dimension d > 2) can be generalized for tensors of arbitrary rank. It is easiest for symmetric, transverse and traceless tensors. However, for some reason, the literature is really obscure. You will find a lot of answers in the paper Symmetric Tensor Spherical Harmonics on the N-Sphere and Their Application to the De Sitter Group SO(N,1) by Higuchi and the references therein. Even though it is never stated there, all the results also hold for scalars and vectors (with certain qualifications, i.e. the scalars are not "traceless" - that does not make sense).

In the 2-dimensional case, (part of) the answer is simple: There are no symmetric transverse traceless tensor harmonics for tensors of rank r > 1. They only exist in 3 or more dimensions.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.