Why an electron "rotate" around the nucleus at a speed close to the light one? I mean where he gets all this energy? One DOES NOT simply approach the speed of light AFAIK.

  • 4
    $\begingroup$ Who said that it does? Non-relativistic QM describes light elements very well. $\endgroup$
    – user10851
    Jul 10, 2013 at 23:36
  • $\begingroup$ I close this question as unclear what you're asking, but the question is really closed because it rests on a false premise. In other words, in order to re-open this question, OP (or somebody else?) should add a published reference that backs up his premise. $\endgroup$
    – Qmechanic
    Jul 11, 2013 at 12:39

1 Answer 1


(1) if it were a classical system, the correct word is "revolve" rather than "rotate"; the Earth rotates every 24 hours and revolves around the sun (approximately) every 365 days

(2) since it's not a classical system, the notion of an electron revolving around the nucleus is suspect. Indeed, for S orbitals, the orbital angular momentum is zero.

So, where do you get this notion that your question is based on?

  • $\begingroup$ That's why I put " around rotate. I don't remember where I have read it... $\endgroup$
    – Hakim
    Jul 11, 2013 at 0:19
  • $\begingroup$ @حكيمالفيلسوفالضائع, perhaps some more research is in order then? $\endgroup$ Jul 11, 2013 at 0:37
  • $\begingroup$ Of course taking the Fourier transform of the position distribution yields a momentum distribution from which you can determine if the semi-classical approximation is adequate to your needs. $\endgroup$ Jul 11, 2013 at 1:28

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