My question is actually my answer to a question I asked myself i.e 'how does potential difference remain same for both capacitors which are connected in parallel, and not get distributed'
When 2 capacitors (lets say, of same capacitence 1F) are connected to a battery of 1V(a source of charges), then the capacitors take some energy from the battery and put some charge inside them (Q=CV=1Coulomb for both capacitors). Which means the battery now has less energy.
Now, if those 2 capacitors were a part of seperate circuits with same volatages, they would still aquire same charge (Q=CV=1 Coulomb) as they did when they were connected in parallel. But in this case the individual batteries( which are part of 2 seperate circuits with a capacitor each) will only loose lower energy each.
So, hence I answer my question as: potential difference across capacitors in parallel remains same becase the battery has a huge supply of energy that will be supplied at some fixed voltage, hence both capacitors can suck up the energy they want from this continously supplying source(but with fixed oomph).
Hence I conclude, the battery with 2 capacitors in parallel will drain out faster than a battery with individual capacitors(considering we charge the capacitors many many times, causing the battery to loose the energy).
Now does this all make sense or its just baloney?