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How occurs the enantiomorph of the mirror?

I would like to know how occurs the RELATIONS OF THE RAYS with the mirror and the image, everything that happens to be flipped image from the right to the left.

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  • $\begingroup$ Have you considered checking wikipedia for some basic definitions and formulas? Then you may come up with a more specific question. $\endgroup$ – Aziraphale Jul 9 '13 at 13:16
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    $\begingroup$ Duplicate? physics.stackexchange.com/q/8227, one of the highest rated questions on this site, so it has some excellent answers :) $\endgroup$ – Kyle Oman Jul 9 '13 at 13:25
  • $\begingroup$ That's good! Thank you for the link, I still need to learn how to find questions just like my question. $\endgroup$ – user73276 Jul 9 '13 at 13:29
  • $\begingroup$ I analyzed all the content of the link, but have not found a physical evidence with the rays. How it travels and all the physical explanation with the rays. $\endgroup$ – user73276 Jul 9 '13 at 13:42
  • $\begingroup$ @Kyle Non sequitur $\endgroup$ – babou Jul 9 '13 at 14:16
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From the link in the comments it should be clear that a mirror does not flip left/right but rather in/out. The mirrored image is flipped at the (surprise!) mirror plane. If you look at the mirror at an angle $\alpha$, you are looking at something that has the same angle between the perpendicular and the point where the "looking-ray" hits the mirror. This is independent of the direction in which you are looking. The physical explanation of the rays can be reduced to: Incoming angle equals outgoing angle.

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