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For example in this figure, I can understand that the charge on plates 1 and 4, and plate 2 and 3 must have the same value because of charge conservation. Is there any justification that plate 2 must have the same charge as plate 1?


2 Answers 2


Is there any justification that plate 2 must have the same charge as plate 1?

In a series circuit the current (charge per unit time) is the same going through all components. That means at any instant in time the positive charge supplied by the positive terminal A making plate 1 positive has to equal the positive charge exiting plate 2 making it equally negative, and so on for all the plates returning to the negative terminal B.

Hope this helps.

  • $\begingroup$ Why the current between plates 1 and 4 is the same as the current between 2 and 3? The circuit is not connected by the gap between plates. $\endgroup$
    – Winniebear
    Mar 26, 2022 at 0:59
  • $\begingroup$ @Winniebear that is how capacitors work - a charge on one side induces the opposite charge on another. So if an electron hits one plate, the other plate frees an electron and the current continues as if the whole thing was a wire. $\endgroup$
    – Señor O
    Oct 21 at 3:32
  • $\begingroup$ I understand that a charge on 1 induces the opposite charge on 4, but why it induces an opposite charge on 2? $\endgroup$
    – Winniebear
    Oct 22 at 7:34

Refer to the posted figure, start with an uncharged capacitor and assume that the free charges in a conductor are positive. The "H"-shaped piece in the middle (from 2 to 3) has zero net charge. When the series combination is connected to the battery, it still has zero net charge because there is no path that will allow charge from the outside to flow in it.

However, the conducting piece from "A" to "1" is an equipotential at the potential of "+" terminal of the battery. The potential was raised by charges amounting to +Q that accumulated on plate "1". Since the entire circuit must have zero net charge, these charges must have come from the conducting piece "4" to "B" whose potential has decreased to match the "-" terminal of the battery. So you have charge Q removed from "4" and added to "1".

How are the free charges in the "H"-shaped piece in the middle going to respond to that? They will be attracted to "4" and pile up on "3" leaving a deficit of charges at "2". In other words, the positive charge on plate "3" is the same as the magnitude of the negative charge on plate "2". Furthermore, these magnitudes must be the same as the magnitudes of the charges on plates "1" and "4" because the entire circuit, as mentioned earlier, has zero net charge.

It's all charge conservation.

  • 1
    $\begingroup$ I don't understand your last sentence. No-one disputes that the charges on 2 and 3 are equal and opposite, but if the magnitude of these charges were (say) half that of the equal and opposite charges on 1 and 4, this wouldn't violate charge conservation (zero net charge). $\endgroup$ Mar 25, 2022 at 19:55
  • $\begingroup$ I agree with Philip Wood. I wrote in the question that charges on 2 and 3 are equal and opposite. What I don't understand is why charge on plate 1 and 2 are equal and opposite $\endgroup$
    – Winniebear
    Mar 26, 2022 at 0:58
  • $\begingroup$ The charges on 1 and 2 must be equal in magnitude because all the field lines that are generated by positive charges on plate 1 must be stopped by an equal number of negative charges on plate 2. That is necessary for the electric field to be zero in the conducting piece 2-3. $\endgroup$
    – AdHoc
    Mar 26, 2022 at 3:18

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