Just started to learn about initial boundary-value problem, and I have came across the concept of decomposing the boundary surface into to disjoint parts, one for stress tensor field and another for displacement vector field. The union of them is the boundary surface of the continuum body and the intersection is zero. I have two questions, first, why do we decompose the boundary surface?, and second why is the intersection between them zero?

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  • $\begingroup$ It's very difficult to tell why without more clarity on the specific nature of the problem you're solving; it might be the case that your exercise involves pulling one part of the continuum while fixing another part, in which case this kind of partition makes it easy to construct a boundary value problem to solve. But like I said, it'll depend on the specific problem. $\endgroup$ Feb 9 at 16:05


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