According to my textbook, the square of orbital period $P_{orb}$ is given by $$P_{\mathrm{orb}}^{2}=\frac{4\pi^{2}a^{3}}{GM},$$ where $a$ is the semi-major axis.
My question is, does the inclination $i$ affect orbital period?
I read that the launch of a rocket often gets help from Earth's angular momentum, for example, if you launch at Earth's equator, the velocity you need to obtain is less than, say, launching near the poles. However, I don't see inclination $i$ being part of the equation for orbital period.
Does the inclination have any effect on orbital period? For example, a planet orbiting around a star at $0^{\circ}$ inclination, would its period change when the inclination rises to $60^{\circ}$?