# Does the inverse square law of sound change with frequency?

High frequency For example, I try to chase wild animals by creating a high sound pressure level with a frequency of 17 kHz or higher, but I can't calculate the initial sound pressure. One thing is because it seems that the attenuation of sound pressure level in the air varies according to the frequency, so it is not possible to do a sufficient calculation with just the inverse square law of sound. If you want to guarantee 140dB with a frequency of 17kHz or higher at a distance of 500m, I would appreciate it if you could tell me the formula how to calculate the initial sound pressure.

• Hello Midas, did you do any research prior to posting your question? If yes, let us know what you currently have, and why it is not sufficient for your needs. Because a very quick google search gives me this page en.wikipedia.org/wiki/Stokes%27s_law_of_sound_attenuation which seems to answer all the points in your question. Also, stack exchange provides a list of questions related to yours where it seems that you would definitely find an answer to your question as written. Commented Jan 24, 2022 at 5:58
• See for example this question which clarifies that Stoke's law and the inverse square law describe two different effects (dissipation in a medium vs. spreading of the energy) and should be taken as complementary to each other, although for propagation in air you can pretty much neglect dissipation and rely only on the inverse square law. Commented Jan 24, 2022 at 6:03