# Confusion on fluid dynamics Bernoulli's equation problem

I couldn't get answer in the choices in this question I started solving by using Continuity equation $$A_1V_1=A_2V_2$$ And calculated $$V_1$$=1.6 m/s

Then i used Bernoulli's equation $$\frac{F}{A_1}+\frac{1}{2}\rho V^2=\rho gh+\frac{1}{2}\rho V_2^2$$ Now when I plug in the values and calculate the force i get a number which isn't in the choices what did I do wrong?

($$\rho$$ is the water density, $$\rho=1000 kg/m^3$$ and $$V$$ is the velocity of the water is the density $$A_1$$ is the area on which the force is applied and $$R_1=50cm$$ ,$$A_2$$ is the area from which the water exits the cylinder (2) $$R_2=20cm$$)

• I'm a bit confused by you using $p$ in the equation, because I am expecting $\rho$ as a density. Please correct this and re-evaluate your answers. Commented Jan 23, 2022 at 15:12

On the right side of Bernoulli's equation, h = 1m, $$V_2$$ = 10 m/sec, and you need to include the atmospheric pressure (where the fluid leaves cylinder 2). The other (h) on the diagram comes from treating the water leaving cylinder 2 as a projectile.