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I've recently stumbled upon a physics problem concerning $\overline{K}\,\!^0$ antimeson production. In this particular example, colliding a $\pi^-$ meson with a stationary proton yields a $K^0$ meson and a $\Lambda^0$ hyperon:

$$\pi^-\,[\overline{u}d] + p\,[uud]\rightarrow K^0\,[d\overline{s}] + \Lambda^0\,[uds]$$

This can be expressed in a Feynman diagram by letting the $u$ and $\overline{u}$ quarks annihilate to a gluon, out of which a pair of $s$-$\overline{s}$-quarks is generated.

However, if a $\overline{K}\,\!^0$ particle would be generated by the same method, in order to conserve the baryon number and the strangeness, more than just a particle must be produced. For example, the following reaction could take place, so that every quantum number is conserved:

$$\pi^-\,[\overline{u}d] + p\,[uud]\rightarrow \overline{K}\,\!^0\,[s\overline{d}] + K^0\,[d\overline{s}] + n\,[udd]$$

However, I can't seem to find a corresponding Feynman diagram for the reaction. I am guessing that the $\Lambda^0$ hyperon decays weakly and somehow yields the antikaon and the neutron, but I can't figure out how... Does anyone have a clue what the Feynman diagram could be?

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There are no very simple diagrams. You need at least one pair production and some kind of flavor changing reaction.

This

enter image description here

includes one pair production and a Drell-Yan flavor change.

There will be others but they will presumably all be equally complicated and therefore unlikely. This will be a low rate event in such systems even when the energy available.

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  • $\begingroup$ Thanks for the clarification. I still have trouble understanding the Feynman diagram you proposed, specifically: what interaction in involved in the $s$-$\overline{s}$-vertex, since there isn't a bosonic line entering it? Also, what exactly is a Drell-Yan flavour change and where does it happen. I have a vague notion of a Drell-Yan process where leptons are created from quark annihilation, but that's it... $\endgroup$ – theSkinEffect Jun 24 '13 at 8:50
  • $\begingroup$ The diagram and my language here are both very loose. Yes the $s$-$\bar{s}$ must come from a boson (likely a gluon) which is not drawn (a short cut common when talking about associated production reactions), and Drell-Yan properly describe annihilation to leptons, but the math is the same to a quark pair and I wanted to explain where I was getting two flavor changes at once. $\endgroup$ – dmckee Jun 24 '13 at 14:57

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