# Does a muon in muonic hydrogen have a longer half-life due to time dilation?

The root mean square speed of an electron in the ground state of hydrogen is very close to the fine structure constant times the speed of light, approximately

$$\frac{c}{137}.$$

This should also be true for the muon replacing the electron in muonic hydrogen. So, I'd expect the muon's half-life to be affected by time dilation. If I'm right, it should be about

$$\frac{1}{\sqrt{1 - \frac{1}{137^2}}} \approx 1.0000266$$

longer than usual. I have two questions, really: is this about right, and has anyone been able to measure this small effect?

When I say "about right", I'm suggesting that it's not exactly right, because I see no reason to compute the expected time dilation by using the root mean square speed: the square root of the expected value of the velocity squared. But it might still be a pretty good estimate.

By the way, here's how you compute the root mean square speed of an electron in its ground state in hydrogen. First you compute the expected value of its kinetic energy, using Schrödinger's equation. This takes real work, but it's done in the first answer here:

$$\langle K \rangle = \frac{\hbar^2}{2ma^2}$$

where $$a$$ is the Bohr radius. But there is a 'velocity squared' operator $$v^2$$ in quantum mechanics such that

$$K = \frac{mv^2}{2}.$$

(It's defined by $$v^2 = p^2/2m$$ where $$p$$ is the usual momentum operator.) So, we get

$$\langle v^2 \rangle = \frac{\hbar^2}{m^2 a^2}.$$

$$a = \frac{\hbar}{m c \alpha}$$

where $$\alpha$$ is the fine structure constant, so a little calculation gives

$$\langle v^2 \rangle = \alpha^2 c^2$$

and the square root of this is $$\alpha c$$. The final result doesn't depend on the mass of the electron so it also applies to the muon.

Here I'm treating both hydrogen and muonic hydrogen using Schrödinger's equation, which is not exact but should be close to right.

• Indeed it's nowhere near relativistic! I showed you using quantum mechanics that according to Schrodinger's equation, the expected value of the square of the speed of the electron in the ground state of hydrogen is the fine structure constant times c - that is, about $c/137$. This has nothing to do with little planets zooming around. (Btw, the electron mass is 511 keV/$c^2$.) Jan 18, 2022 at 23:21
• probably irrelevant but besides $\gamma(\langle v\rangle)$ maybe one could also try $\langle \gamma(v)\rangle$ Jan 21, 2022 at 15:12
• I bet that's more accurate; they should be pretty close for energy eigenstates of hydrogen but not for heavy elements. I got into this because a crude calculation says "the innermost electrons of mercury move at 58% the speed of light". Then someone asked me about time dilation for muonic hydrogen and I realized I didn't know whether it's been studied. Jan 21, 2022 at 16:29
• Muonic hydrogen is too light to see the effect, but time dilation has been observed for very heavy muonic atoms. The answer to Would superheavy muonic atoms be more stable than light muonic atoms such as muonic helium (hydrogen 4.1)? maybe be helpful. Oct 6, 2022 at 4:47
• Concretely, one can perform this calculation by evaluating the matrix element $\langle e^- \bar{\nu}_e \nu_\mu | L_{\mathrm{eff}} | \mu^- \rangle$ where $|\mu^- \rangle$ is the initial state, and $L_{\mathrm{eff}}$ is the four-fermion operator mediating the decay, and then integrating over final state momenta. Standard QFT tells us this yields a time dilated decay rate for a moving free muon, as expected. For a bound muon, the matrix element will involve an integral over its wavefunction. I'm 99% sure it'll produce the expected time dilation effect, but haven't checked since it seems clunky. Jan 5 at 23:44

Your calculation for the time dilation effect is correct, but the muon in muonic hydrogen actually has a shorter lifetime than a free muon because the time dilation lifetime increase is much less than the reduction due to $$\mu^- p \rightarrow n \nu_\mu$$ captures. We are close to, but do not yet have, sufficient experimental and theoretical accuracy to observe the time dilation effect in muonic hydrogen. As noted in this answer, however, the time dilation effect has likely been observed in heavier muonic atoms.
Your calculation of the time dilation effect agrees with those of Überall ("Decay of μ− Mesons Bound in the K Shell of Light Nuclei", Eq. 44b) and Silverman ("Relativistic time dilation of bound muons and the Lorentz invariance of charge", Eq. 3).Überall actually has $$1-\alpha_{\mathrm{QED}}^2/2$$ after a more rigorous calculation instead of $$\sqrt{1-\alpha_{\mathrm{QED}}^2}$$, but they are equivalent to this order. The change in the muon decay rate due to time dilation in muonic hydrogen is: $$\Delta_{\mathrm{rel}}^{\mathrm{th}}=\frac{\sqrt{1-\alpha_{\mathrm{QED}}^2}-1}{\tau_\mu}=\frac{-2.663 \times 10^{-5}}{2.196981 \times 10^{-6}\,\mathrm{s}}=-12.1 \,\mathrm{s^{-1}}$$
I believe the best experimental measurement of the muonic hydrogen capture rate ($$\Lambda_S$$) is MuCap Collaboration's paper on "Measurement of Muon Capture on the Proton to 1% Precision and Determination of the Pseudoscalar Coupling $$g_{P}$$":
$$\Lambda_S^{\mathrm{exp}}=714.9 \pm 5.4\,(stat) \pm 5.1\,(syst) \,\mathrm{s^{-1}}$$
So the decreased decay rate ($$\rightarrow$$lifetime increase) due to time dilation is 60 times less than the increased decay rate ($$\rightarrow$$lifetime decrease) due to muon capture by the hydrogen nucleus. At the time of the MuCap measurement in 2013, the expected value for the capture rate, based on earlier experimental and theoretical values, was $$\Lambda_S^{\mathrm{th}}=712.7 \pm 3.0 \pm 3.0 \,\mathrm{s^{-1}}$$ in good agreement with experiment: $$\Lambda_S^{\mathrm{exp}}-\Lambda_S^{\mathrm{th}}=2.2 \pm 6.2\,(stat) \pm 6.0\,(syst) \,\mathrm{s^{-1}}$$