You ignored the $k$ term, but it's crucial here. $k$ is the curvature not of spacetime but of constant-$t$ spatial slices, so it depends not only on spacetime curvature (represented by $ρ$ and $Λ$) but also on the extrinsic curvature of the spatial slice in the spacetime (represented by $\dot a/a$). You can think of this equation as showing the relationship between the spatial curvature that appears in the metric and the physical spacetime curvature.
In the special case $Λ=ρ=0$, the equation becomes $\displaystyle H^2 = \frac{-kc^2}{a^2}$, which implies $R = c/|H|$, where $R=\sqrt{|k|}/a$ is the radius of curvature. ($k/a^2$ is the Gaussian curvature.)
If also $p=0$, then there is no Riemann curvature, the spacetime is Minkowski space, and this equation is easy to interpret: the radius of curvature equals the time since the big bang (or until the big crunch). This makes sense because surfaces of constant $t$ are surfaces of constant distance from the $t\to0$ limit of all comoving worldlines, which is a single point in Minkowski space. In Euclidean space, the points at a distance $R$ from a point form a sphere with curvature radius $R$; in Minkowski space the points at a timelike distance $R/c$ form a hyperbolic plane with curvature radius $R$.
The spatial curvature has, in this special case, no physical significance: you can cover the same region of spacetime with many different FLRW charts with different values of $k$ and $H$. It's a coordinate artifact.
When $ρ\ne 0$, the symmetry is broken by the presence of matter, and the FLRW coordinates are dictated by the broken symmetry, so it is not a pure coordinate artifact, but the equation still expresses the relationship between inherent curvature and the curvature of a particular coordinate system, and not a physical force.