I`m trying to write an expression ( Work & Energy ) of spring that is not loose and it has a box on it with a weight of 1Kg.
how its should be? this is what I tried to do:
$$\frac{kx^2}{2}-mg$$ this is an illustration of it.
enter image description here

the $m$ box is $1kg$ and $k=200$ and the state is that the spring is not loose. I would like to get some advice how to do that.

Here is my full problem. I want to find the maximum contraction of the spring, The first mass falls on the mass already in the spring. so I chose to solve it with Work and Energy.
$$mg(3+x_{0})+\frac{k{x_{0}}^2}{2}-mg=\frac{k{x_{0}}^2}{2}-3g$$ this is the right expression to write?

the full problem

  • $\begingroup$ may you define $k$? $\endgroup$ – al-Hwarizmi Jun 15 '13 at 11:49
  • $\begingroup$ Elastic coefficient $\endgroup$ – Ofir Attia Jun 15 '13 at 11:53
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    $\begingroup$ and what is $kx^2/2$ and its dimension? $\endgroup$ – al-Hwarizmi Jun 15 '13 at 11:55
  • $\begingroup$ Work of spring $ W = \int^t_0 Fvdt = \int^t_0 kxv_{x}dt=\frac{1}{2}kx^2$ en.wikipedia.org/wiki/Work_(physics) $\endgroup$ – Ofir Attia Jun 15 '13 at 12:02
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    $\begingroup$ @OfirAttia : Don't mix variables and numerical values: it is unreadable : When we see an expression, we must check directly if the units are correct, in your expressions, we see together $mg(3+x0), mg, 3g$. This is a nonsense. If you use variables, use variables only. If, at the end, you want to test numerical values, use numerical values for everything, but do not mix the 2. $\endgroup$ – Trimok Jun 15 '13 at 17:44

$$W = \int^t_0 Fvdt = \int^t_0 kxv_{x}dt=\frac{1}{2}kx^2$$ $$G=mg$$

Then under static balance:



You are correct!

  • $\begingroup$ ok, if its right to write it like that, I added my full problem in Work and Energy, if you can write me some comments on that. thanks. $\endgroup$ – Ofir Attia Jun 15 '13 at 12:21
  • $\begingroup$ what is your $G$ and your $W$ in the new balance situation? $\endgroup$ – al-Hwarizmi Jun 15 '13 at 13:08
  • $\begingroup$ @al-Hwarizmi : Same remark as for Ofir Attia (see above) : Don't mix variables and numerical values: it is unreadable. (mg has not the dimension of an energy) $\endgroup$ – Trimok Jun 15 '13 at 17:46
  • $\begingroup$ I am myself meanwhile confused. The set up of the question needs to be really calibrated to a norm of notation. Sorry but cannot help more. $\endgroup$ – al-Hwarizmi Jun 15 '13 at 18:20

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