# Fluid in beaker on inclined plane

On an inclined plane there is a beaker filled with fluid, what will be the shape of fluid as the beaker accelerates down? What I think is that the beaker accelerates with $$g \sin\theta$$ acceleration down the incline and so does the fluid molecules of surface, so fluid molecules experience a net real force down the incline of $$mg\sin\theta$$, and $$mg\cos \theta$$ perpendicular to the inclined plane due to $$mg$$ component, so the net force is $$mg$$ down only, and fluid should take a horizontal shape (perpendicular to net force) but as I have seen answer isn't this, the solution takes into consideration a pseudo force.I don't get where my method is wrong, isn't fluid perpendicular to real force?

• Hi. Please try and use Latex for rendering formulas/math. For simple formulas include them between \$ signs. Also, draw an FBD to see the light in this simple problem.
– Gert
Nov 26 '21 at 11:31
• Ok, I am new here so didn't knew latex worked here also. I have added the diagram of what I expect can u check pls Nov 26 '21 at 11:37

There is also the normal reaction force from the bottom of the beaker of value $$mg\cos\theta$$, so the resultant force on the fluid is the $$mg\sin\theta$$ component going down the plane.