1
$\begingroup$

I'm a computer scientist and right now I'm trying to end the research work for my master thesis and a basic problem of quantum mechanics is blocking me.

I'm trying to do a probability calculus of the action of measuring a qubit in a wrong bases. In bibliography, I've always found the statement:

When Bob chooses the wrong bases for measuring a qubit then the result will be completely random.

But what exactly does that mean? The results will be Non-deterministic (using theoretical CS terms) and then the probability cannot be calculated or that mean that the probability of the result is exactly $\frac{1}{2}$0 and $\frac{1}{2}$1?


Cross-posted on crypto.SE

$\endgroup$
4
  • 1
    $\begingroup$ I recommend Feynmann lectures (the quantum mechanics part) for simple but correct explanations. It is essentially what Stern-Gerlach device does (replace qubit by two-level atom/spin and you have it). $\endgroup$ Nov 26 '21 at 11:42
  • $\begingroup$ My physics background is a little bit poor, however, you mean this? feynmanlectures.caltech.edu/III_10.html $\endgroup$
    – VitoShade
    Nov 26 '21 at 12:41
  • $\begingroup$ I would say earlier: this one; Spin one-half, but the preceding one can be useful as well, since it explains teh Stern-Gerlach apparatus. Don't be misled by quantum computing buzz-words - qubit is just a two-level system, and spin-1/2 is the simplest one. Physical realization of a TLS may be different, but the math and probabilistic interpretation remain the same. $\endgroup$ Nov 26 '21 at 12:57
  • $\begingroup$ I assume the "right" basis is the computational basis $|0\rangle, |1\rangle$, what is the wrong basis? You should define the setting and terms. $\endgroup$ Nov 26 '21 at 14:08

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.