# Heisenberg Uncertainty Principle: How does this uncertainty compare to the energy of the transition?

An atom meets one of its electrons in an excited state. The average time that this remains in that state is $$1 × 10^{−8}$$ s to emit a photon of wavelength $$620$$ nm or $$2$$ eV energy.

My questions are: How does this uncertainty compare to the energy of the transition? To what corresponds the variation in wavelength that it emits in average those atoms?

I already have the uncertainty in the energy of that excited state, $$E≥h/t = 4.96\times 10^{-9} eV$$

• The 2eV is the average energy of the transition, but it has a natural linewidth around it. WP. Nov 24 at 14:31