Does the resistance of a filament lamp change?

Recently in a work book there has been a question to explain with the aid of a circuit diagram the method a student could use to investigate how the resistance of a single lamp changes with potential difference across the lamp. However I am unsure how to approach this question. Does the resistance of the filament lamp change with potential difference and current? If so, what is the relationship between them? How do I approach this tricky question? I have tried applying the equation to solve the problem but unfortunately to no avail

$$V=\frac{I}{R} \mathcal{L}$$

Any help and guidance would be incredibly helpful. ;)

Filaments are, quite deliberately by their construction, nonlinear resistors. That means their voltage-current characteristic doesn't follow the well-known Ohm's law $$U = R \cdot I$$ with a constant $$R$$, but rather $$R$$ varies with the applied voltage $$U$$ (or the current $$I$$, which is equivalent, but the question states resistance change with potential difference). So we could write $$U = R(U) \cdot I \qquad \text{or} \qquad R(U) =\frac{U}{I}$$
From here, you can try to continue yourself. How would you go on to find $$R(U)$$ from this expression? What experimental setup can you think of to get the data you need?